我使用Objective-C
下面的代码弹出特定的代码ViewController
。
for (UIViewController *controller in self.navigationController.viewControllers) {
if ([controller isKindOfClass:[AnOldViewController class]]) {
//Do not forget to import AnOldViewController.h
[self.navigationController popToViewController:controller
animated:YES];
break;
}
}
我该如何在Swift中做到这一点?
尝试以下代码:
for controller in self.navigationController!.viewControllers as Array {
if controller.isKind(of: ViewController.self) {
self.navigationController!.popToViewController(controller, animated: true)
break
}
}
对于Swift 3+
let viewControllers: [UIViewController] = self.navigationController!.viewControllers
for aViewController in viewControllers {
if aViewController is YourViewController {
self.navigationController!.popToViewController(aViewController, animated: true)
}
}
迅捷4.0
for controller in self.navigationController!.viewControllers as Array {
if controller.isKind(of: DashboardVC.self) {
_ = self.navigationController!.popToViewController(controller, animated: true)
break
}
}
这是完美的工作。
迅捷5
弹出特定类的最新实例,例如SomeViewController
:
navigationController?.popToViewController(ofClass: SomeViewController.self)
但是您需要添加以下UINavigationController
扩展名:
extension UINavigationController {
func popToViewController(ofClass: AnyClass, animated: Bool = true) {
if let vc = viewControllers.last(where: { $0.isKind(of: ofClass) }) {
popToViewController(vc, animated: animated)
}
}
}
我更喜欢一种通用的方法。
我有UINavigationController的扩展名:
extension UINavigationController {
func backToViewController(vc: Any) {
// iterate to find the type of vc
for element in viewControllers as Array {
if "\(element.dynamicType).Type" == "\(vc.dynamicType)" {
self.popToViewController(element, animated: true)
break
}
}
}
}
假设我有一个在导航堆栈中实例化的FOHomeVC类(它是一个UIViewController)。
所以我会在我的代码中这样做:
self.navigationController?.backToViewController(FOHomeVC.self)
我添加了一个扩展,UINavigationController
可帮助您查找导航堆栈中是否存在该控制器。如果是,则它将弹出到该控制器,否则您将传递新控制器以使用pushController
参数进行推送。
extension UINavigationController {
func containsViewController(ofKind kind: AnyClass) -> Bool {
return self.viewControllers.contains(where: { $0.isKind(of: kind) })
}
func popPushToVC(ofKind kind: AnyClass, pushController: UIViewController) {
if containsViewController(ofKind: kind) {
for controller in self.viewControllers {
if controller.isKind(of: kind) {
popToViewController(controller, animated: true)
break
}
}
} else {
pushViewController(pushController, animated: true)
}
}
}
从导航堆栈中找到视图控制器,然后弹出该视图控制器(如果存在)
for vc in self.navigationController!.viewControllers {
if let myViewCont = vc as? VCName
{
self.navigationController?.popToViewController(myViewCont, animated: true)
}
}
迅捷5
let controllers : Array = self.navigationController!.viewControllers
self.navigationController!.popToViewController(controllers[1], animated: true)
迅捷4 /迅捷5
for controller in self.navigationController!.viewControllers as Array {
if controller.isKind(of: HomeViewController.self) {
self.navigationController!.popToViewController(controller, animated: true)
break
}
}
迅速地
@IBAction func popToConversationsVC(_ sender: UIButton) {
if (self.navigationController != nil) {
for vc in self.navigationController!.viewControllers {
if vc is ConversationsVC {
self.navigationController?.popToViewController(vc, animated: false)
}
}
}
}
我更喜欢“真正的通用”且功能更多的方法。
所以我想出了以下UINavigationController
扩展功能。您还可以将first函数用于其他任何事情,您只需要访问导航堆栈中的特定VC。
扩展名
extension UINavigationController {
func getViewController<T: UIViewController>(of type: T.Type) -> UIViewController? {
return self.viewControllers.first(where: { $0 is T })
}
func popToViewController<T: UIViewController>(of type: T.Type, animated: Bool) {
guard let viewController = self.getViewController(of: type) else { return }
self.popToViewController(viewController, animated: animated)
}
}
用法
self.navigationController?.popToViewController(of: YourViewController.self, animated: true)
这至少应该在Swift 4和5中有效。
@PabloR的Swift 5答案在这里:
extension UINavigationController {
func backToViewController(vc: Any) {
// iterate to find the type of vc
for element in viewControllers as Array {
if "\(type(of: element)).Type" == "\(type(of: vc))" {
self.popToViewController(element, animated: true)
break
}
}
}
}
用法:
self.navigationController?.backToViewController(vc: TaskListViewController.self)
请针对Swift 3.0使用以下代码:
let viewControllers: [UIViewController] = self.navigationController!.viewControllers as [UIViewController];
for aViewController:UIViewController in viewControllers {
if aViewController.isKind(of: YourViewController.self) {
_ = self.navigationController?.popToViewController(aViewController, animated: true)
}
}
我需要使用它,因为在某些情况下应用程序崩溃:
if let navVC = self.navigationController {
let views = navVC.viewControllers as Array
for controller in views {
if controller.isKind(of: YourVC.self) {
navVC.popToViewController(controller, animated: true)
return
}
}
}
extension UINavigationController {
func popBack(to vc: AnyClass, animated: Bool = true) {
guard let elementFound = (viewControllers.filter { $0.isKind(of: vc) }).first else {
fatalError("cannot pop back to \(vc) as it is not in the view hierarchy")
}
self.popToViewController(elementFound, animated: animated)
}
}
没有力的简单和最佳解决方案是
if let vc = navigationController.viewControllers.filter({$0 is YourViewController}).first as? YourViewController {
self.navigationController.popToViewController(vc, animated: true)
}
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文章标签:ios , swift , uiviewcontroller
版权声明:本文为原创文章,版权归 admin 所有,欢迎分享本文,转载请保留出处!
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